问题 填空题

(共15分) I(9分)写出下列热化学反应方程式

(1)N2 (g)与H2(g)反应生成1molNH3(g),放出46.1KJ热量。

                                                               

(2)1molC2H5OH(l)完全燃烧生成CO2(g)和H2O(l),放出1366.8KJ热量。

                                                               

(3)1molC(石墨)与适量H2O(g)反应吸收131.3KJ热量

                                                               

II .(6分)(1)化学反应中均伴随着能量的变化,化学键的断裂和形成是发生能量变化的主要原因。生成物中化学键形成时会__________能量(填“放出”或“吸收”);如果一个化学反应,化学键断裂时的能量变化大于化学键形成时的能量变化,则该反应属于_________反应;如果一个化学反应,反应物的总能量和生成物的总能量有如图所示的关系,则该反应属于__________反应。

(2)不同形式的能量可以相互转换,如:化学能和电能、热能之间的相互转换。如图是一个原电池工作原理的示意图。试回答:

①从能量角度看,它属于____________能转化为____________能;

②装置中Zn为____________极。

答案

(18分)I(1)1/2N2(g)+3/2H2(g)=NH3(g)  △H=-46.1 kJ·mol-1

(2)C2H5OH(g)+3O2(g)==2CO2(g)+3H2O(l);△H=-1366.8 kJ·mol-1

(3)C(石墨s)+H2O(g)="=" CO(g)+ H2(g);△H=131.3 kJ·mol-1(每空2分)

II(1)放出  吸热 放热 (2)①化学 电 ②负   (每空1分)

I热化学方程式的书写,注意物质的状态,计量数,吸放热与△H的 “+”“ -”号间关系。

(1)1/2N2(g)+3/2H2(g)=NH3(g)  △H=-46.1 kJ·mol-1

(2)C2H5OH(g)+3O2(g)==2CO2(g)+3H2O(l);△H=-1366.8 kJ·mol-1

(3)C(石墨s)+H2O(g)="=" CO(g)+ H2(g);△H=131.3 kJ·mol-1

II(1)放出  吸热 放热 (2)①化学 电 ②Zn为活泼金属,作负极。   

单项选择题 案例分析题
完形填空

阅读下面短文并回答问题,然后将答案写在横线上(请注意问题后的词数要求)

[1]Perhaps you are an average student with average intelligence. However, you can receive better grades if you want. Yes, even students with average intelligence can be top students without additional work. Here’s how:

[2]Plan your time carefully. Make a list of your weekly tasks. Then make a schedule of your time. Be sure to set aside enough time to complete your normal reading and work assignments. Of course, studying shouldn’t occupy all of the free time on the schedule.

[3]Make good use of your time in class. Listening to what the teacher says in class means less work later. Take notes to help you remember what the teacher says.

[4]Skim before you read. Look over a passage quickly before you begin to read it more carefully. As you preview the material, you get some idea of the content and how it is organized. Later when you begin to read you will recognize less important material and you may skip some of these portions. Skimming helps double your reading speed and improve your comprehension as well.

[5]_____, Go over your notes as soon as you can after class. Review important points mentioned in class as well as points you remain confused. If you know what the teacher will discuss the next day, skim and read that material, too. If you review your notes and textbook regularly, the material will become more meaningful and you will remember it longer. Regular review leads to improved performance on tests.

[6]Develop a good attitude towards tests. The purpose of a test is to show what you have learned about a subject. The world won’t end if you don’t pass a test, so don’t worry excessively about a single test.

[7]There are other techniques that might help you with your studying. Improving your studying habits will improve your grades.

小题1:What’s the main idea of the passage?(no more than 8 words)

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小题2:What should you do if you fail a test?(no more than 4 words)

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小题3:Please fill in the blank in the fifth paragraph with proper words.(no more than 4 words)

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小题4:According to the passage, how can an average student improve his/her grades?(no more than 6 words)

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小题5:What does the word “it”(line 4, paragraph 5)probably refer to?(no more than 3 words)

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