问题
解答题
解方程: (1)x2-2x=2x-4; (2)y2-2
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答案
(1)原方程化为:x(x-2)-2(x-2)=0,即(x-2)2=0,
解得,x1=x2=2;
(2)原方程化为:y2-2
y+2=0,3
∵△=(2
)2-8=4>0,3
∴x1=
+1,x2=3
-1.3
解方程: (1)x2-2x=2x-4; (2)y2-2
|
(1)原方程化为:x(x-2)-2(x-2)=0,即(x-2)2=0,
解得,x1=x2=2;
(2)原方程化为:y2-2
y+2=0,3
∵△=(2
)2-8=4>0,3
∴x1=
+1,x2=3
-1.3