问题
选择题
已知8x+1<-2x,则下列各式中正确的是( )
A.10x+1>0
B.10x+1<0
C.8x-1>2x
D.10x>-1
答案
∵8x+1<-2x,
∴8x+2x+1<-2x+2x,
即10x+1<0.
故选B.
已知8x+1<-2x,则下列各式中正确的是( )
A.10x+1>0
B.10x+1<0
C.8x-1>2x
D.10x>-1
∵8x+1<-2x,
∴8x+2x+1<-2x+2x,
即10x+1<0.
故选B.