问题
选择题
已知：O2(g) = O2+(g)+e- △H1= +1175.7 kJ·mol-1
PtF6-(g) =PtF6(g)+e- △H2= +771.1 kJ·mol-1
O2+(g)+PtF6-(g) =O2PtF6(s) △H3= -482.2 kJ·mol-1
则反应O2(g)+PtF6(g) = O2PtF6(s)的△H是 [ ]
A．77.6 kJ
B．-77.6 kJ·mol-1
C．+77.6kJ·mol-1
D．-886.8kJ·mol-1
答案
答案：B