问题
解答题
(1)用配方法解方程:x2-4x+1=0
(2)用因式分解法解方程:3(x-5)2=2(5-x)
答案
(1)x2-4x+4=3,
(x-2)2=3,
x-2=±
,3
则x1=2+
,x2=2-3
;3
(2)3(x-5)2+2(x-5)=0,
(x-5)[3(x-5)+2]=0,
x-5=0或3(x-5)+2=0,
x1=5,x2=
.13 3
(1)用配方法解方程:x2-4x+1=0
(2)用因式分解法解方程:3(x-5)2=2(5-x)
(1)x2-4x+4=3,
(x-2)2=3,
x-2=±
,3
则x1=2+
,x2=2-3
;3
(2)3(x-5)2+2(x-5)=0,
(x-5)[3(x-5)+2]=0,
x-5=0或3(x-5)+2=0,
x1=5,x2=
.13 3