问题
选择题
函数y=cos2xcos
|
答案
y=cos2xcos
+sin2xsinπ 5
=cos(2x-π 5
)π 5
令2kπ≤2x-
≤π+2kππ 5
∴kπ+
≤x≤ kπ+π 10 3π 5
故选B.
函数y=cos2xcos
|
y=cos2xcos
+sin2xsinπ 5
=cos(2x-π 5
)π 5
令2kπ≤2x-
≤π+2kππ 5
∴kπ+
≤x≤ kπ+π 10 3π 5
故选B.