在密闭容器中进行反应:H2(g)+Br2(g)
2HBr(g) ΔH<0,达到平衡后,欲使颜色加深,应采取的措施是( )
A．升高温度
B．降低温度
C．增大H2浓度
D．减小压强
答案：A
欲使颜色加深,则Br2的浓度应变大。该反应为放热反应,升温平衡向左移动,Br2的浓度变大,因此颜色加深。增大氢气浓度,平衡向右移动,Br2的浓度减小,颜色变浅。减小压强通过增大容器体积实现,平衡不移动,但Br2的浓度减小,颜色变浅。
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