问题 写作题

第二节:书面表达(满分25分)假如你是一名高三学生
假如你是一名高三学生最近你班同学就填报志愿时是首先考虑专业还是学校有两种不同的看法。
观点
理由
首先选择专业
1. 可以学习自己感兴趣的东西;
2. 便于将来从事自己喜爱的工作。
首先选择学校
1. 学习环境对人的成长很重要;
2. 名牌大学的毕业生在求职时常会受到青睐。
你的看法
 
 
请你根据此表的内容,写一篇短文。
注意:1.开头已给出,不计入总词数;
2.词数100左右。   
Every student in Senior Three will be faced with the question when he passes the College-Entrance Examinations.                                                                        
______________________________________________________________________________  ______________________________________________________________________________                                                                                     
Yours truly,
Liu Wei
答案

Every student in senior 3 will be faced with the question when he passes the College-Entrance Examination. Should he choose a good major or a good university first? Some students prefer to choose majors first so that they can learn what they are interested in. It will also make it possible for them to take their favorite jobs in the future.

However, those who think differently believe that good universities have better teachers and better conditions. The graduates from leading universities are often more likely to find a good job. In my opinion, the best choice is a good major, because no matter where we study, we can still achieve a lot if we try our best. Doing whatever we are fond of will benefit us. It will lead to our great achievements.

单项选择题 A1型题
问答题

(1)在“用单摆测定重力加速度”的实验中

①为了较准确地测出重力加速度,可选用的器材为______(填正确选项的序号)

A.40cm长的结实细线、小木球、秒表、米尺、铁架台

B.40cm长的结实细线、小钢球、秒表、米尺、铁架台

C.100cm长的结实细线、小钢球、秒表、米尺、铁架台

D.100cm长的结实细线、大木球、秒表、米尺、铁架台

②用游标为10分度的卡尺测量小球的直径,某次测量的示数如图所示,读出小球直径d的值为______m.

③某次测得单摆摆线的长度为L(m),小球直径为d(m),此单摆完成n次全振动所用时间为t(s),则重力加速度可表示为g=______.

(2)某研究性学习小组欲用图1所示的电路,测定一节干电池的电动势和内阻.

①先直接用多用电表测定该电池的电动势.在操作无误的情况下,多用电表表盘示数如图2,其示数为______V.

电池的内阻较小,为了防止在调节滑动变阻器时造成短路,电路中用一个定值电阻R0起保护作用.除电池、开关和导线外,可供选用的实验器材还有:

电流表:A(量程0~0.6A,内阻约为0.1Ω);(量程0~3A,内阻约为0.05Ω);

电压表:V(量程0~3V,内阻约6kΩ);(量程0~15V,内阻约15kΩ);

定值电阻:R0(阻值1Ω);(阻值10Ω);

滑动变阻器:R(阻值范围0~10Ω、额定电流2A)(阻值范围0~1kΩ、额定电流1A)

②为了调节方便,测量准确,实验中应选用电流表的量程为______,电压表的量程为______,定值电阻R0的阻值为______,滑动变阻器的阻值范围为______.

③根据电路图,在下图3所示的实物上画出连线(部分线已画出).

④按正确的器材连接好实验电路后,接通开关,改变滑动变阻器的阻值R,读出对应的电流表的示数I和电压表的示数U,并作记录.某同学记录的实验数据如下表所示,试根据这些数据在图4中画出U-I图线.

123456
I/A0.100.150.200.250.300.40
U/V1.321.251.181.181.040.90
⑤根据图线得到被测电池的电动势E=______V,内电阻r=______Ω(结果保留三位有效数字).

⑥用该实验电路测出的电动势值E______实际值;内阻R______实际值.(选填“>”、“<”或“=”)

⑦引起该实验系统误差的主要原因是______.

A.由于电压表和电流表读数不准确引起误差

B.用图象法求E和r时,由于作图不准确造成误差

C.由于电压表的分流作用造成电流表读数总是比电源实际输出的电流小

D.保护电阻R0的使用.