解方程:
(1)2x2-5=4x
(2)x2-4x+1=0
(3)(x-2)2-4(x+1)2=0.
(1)2x2-5=4x,
2x2-4x=5,
x2-2x=
,5 2
x2-2x+1=
+1,5 2
(x-1)2=
,7 2
x=±
+1,14 2
x1=
+1,x2=-14 2
+1;14 2
(2)x2-4x+1=0,
x2-4x=-1,
x2-4x+4=-1+4,
(x-2)2=3,
x-2=±
,3
x1=
+2,x2=-3
+2;3
(3)(x-2)2-4(x+1)2=0,
[(x-2)+2(x+1)][(x-2)-2(x+1)]=0,
3x•(-x-4)=0,
x1=0,x2=-4.