问题 阅读理解

American researchers say drinking tea may help strengthen the body’s defense system against infection. Doctors at Brigham and Women’s Hospital in Boston, Massachusetts, did the study. The team studied a chemical found in black, green, oolong and pekoe tea. This chemical is an amino acid called L-theanine. The scientists say it may increase the strength of gamma delta T cells. That’s the letter T, not the drink. Gamma delta T cells are part of the body’s defense.

First, the researchers mixed some of these cells with antigens found in the amino acid(氨基酸). Antigens help the body react to infection. Then the scientists added some bacteria. Within twenty-four hours, the cells produced a lot of interferon, a substance that fights infection. Cells not mixed with the antigens did not produce interferon.

In the second part of the study, eleven people drank five to six cups of black tea every day. Ten other people drank the same amount of instant coffee. That is dried coffee mixed with hot water.

Two weeks later, and again two weeks after that, the researchers tested the blood of all twenty-one people. They also looked at what happened when they added bacteria to the blood cells. They found that the tea drinkers produced five times more interferon after they started drinking tea. The coffee drinkers did not produce interferon.

Doctor Jack Bukowski led the study. He says the antigens added to the gamma delta T cells were responsible for the increased reaction to the bacteria. He says that the study also showed that the cells were able to remember the bacteria and fight them again the next time.

Earlier research already has found that tea can help prevent heart disease and cancer. Doctor Bukowski says the new study must be repeated by more people. “If the findings prove to be true,” he says, “then tea drinking might also help protect against bacterial infections.” He says the amino acid L-theanine could be removed from the tea and used as a drug to strengthen the body’s defenses.

小题1:We may know from the text that ______ can be found in different kinds of tea.

A.L-theanine

B.Gamma delta T cells

C.interferon

D.bacteria小题2:Tea may help strengthen the body’s defense system because it helps ______.

A.to add some bacteria to the blood cells

B.the body to produce more gamma delta T cells

C.the body to produce more interferon

D.to mix antigens with some of the cells in the body小题3:According to Dr Bukowski, ______.

A.the findings of the study have already proved to be true

B.further study is needed to prove the findings true

C.he has taken some amino acid L-theanine from tea and made a drug with it

D.he is not sure whether tea help prevent heart disease and cancer小题4:What would be the best title for this text?

A.Tea Is Better than Coffee

B.Our Body Needs Tea

C.Tea Can Help Prevent Cancer

D.Tea May Help Fight Infection

答案

小题1:A

小题2:C

小题3:B

小题4:D

题目分析:这篇文章讲的是喝茶可以增强身体对感染的抵御能量力,因为它可以使身体制造出更多的干扰素。

小题1:细节题:从第一段的句子:The team studied a chemical found in black, green, oolong and pekoe tea. This chemical is an amino acid called L-theanine.可知不同的茶里面都有的物质是L-theanine ,选A

小题2:细节题:从第二段的句子:the researchers mixed some of these cells with antigens found in the amino acid(氨基酸). Antigens help the body react to infection 可知茶有助于加强身体的免疫力因为它可以使身体制造出更多的干扰素,选C

小题3:细节题:从最后一段的句子:Doctor Bukowski says the new study must be repeated by more people. 可知Doctor Bukowski 认为要证明这个发现是真的,还需要更多的研究,选B

小题4:主旨题:纵观全文和第一段的句子:American researchers say drinking tea may help strengthen the body’s defense system against infection. 可知这篇文章讲的是喝茶可以增强身体对感染的抵御能量力,选D

多项选择题

请编制程序ex9.ASM,其功能是:从20个有符号字节数据中取出负数并计算其绝对值之和(字型),然后存放在指定的内存区中,多余的空间填0。
例如:
内存中有80H,02H,00H,7CH,7BH,11H,……
结果为80H,00H,FEH,00H,FDH,00H,85H,00H,……
部分程序已给出,其中原始数据由过程LOAD从文件INPUT1.DAT中读入SOURCE开始的内存单元中,运算的结果要求从RESULT开始存放,由过程SAVE保存到文件OUTPUT1.DAT中。补充BEGIN和END之间已给出的源程序使其完整(空白已用横线标出,每行空白一般只需一条指令,但采用功能相当的多条指令亦可),或删除BEGIN和END之间原有的代码并自行编程来完成要求的功能。
对程序进行汇编,并与IO.OBJ链接产生执行文件,最终运行程序产生结果。调试中发现整个程序中存在错误之处,请加以修改。
[试题程序]
EXTRN LOAD:FAR,SAVE:FAR
N EQU 20
STAC SEGMENT STACK
DB 256 DUP()
STAC ENDS
DATA SEGMENT
SOURCE DB N DUP()
RESULT DB N DUP(0)
NAME0 DB ’INPUT1.DAT’,0
NAME1 DB ’OUTPUT1.DAT’,0
DATA ENDS
CODE SEGMENT

ASSUME CS:CODE,DS:DATA,SS:STAC
START PROC
FAR
PUSH DS
XOR
AX,AX
PUSH
AX
MOV
AX,DATA
MOV DS,AX
MOV
ES,AX
LEA DX,SOURCE
;数据区起始地址
LEA
SI,NAME0
;原始数据文件名
MOV
CX,N
;字节数
CALL LOAD
;从’INPUT1.DAT’中读取数据
; **** BEGIN ****
LEA
SI,SOURCE
LEA DI,RESULT
MOV DX,0
MOV
CX,N
CLD
CON:LODSH
(1)
JGE
(2)
MOV
[DI],AL
INC DI
(3)
INC DIADD DL,AL
(4)
NEXT:LOOP
CON
MOV
[DI],DXADD DI,2
MOV
CX,40
SUB
CX,DI
MOV
AL,0
(5)
; ****END****
LEA DX,RESULT
;结果数据区首址
LEA
SI,NAME1
;结果文件名
MOV
CX,N
;结果字节数
CALL
SAVE
;保存结果到文件
RET
START ENDP
CODE
ENDS
END
START

单项选择题