问题
填空题
计算1+2-3+4+5-6+7+8-9+…+1999+2000-2001+2002+2003=______.
答案
原式=(1+2-3)+(4+5-6)+(7+8-9)+…+(1999+2000-2001)+2002+2003
=0+3+6+…+1998+2002+2003
=(3+1998)×
+40051998 3 2
=666333+4005
=670338.
计算1+2-3+4+5-6+7+8-9+…+1999+2000-2001+2002+2003=______.
原式=(1+2-3)+(4+5-6)+(7+8-9)+…+(1999+2000-2001)+2002+2003
=0+3+6+…+1998+2002+2003
=(3+1998)×
+40051998 3 2
=666333+4005
=670338.