若给fun函数的形参s传送字符串“∪∪6354’abc"(其中∪表示空格字符)，则函数的返回值是 【19】 。
long fun(char s[])
long n; int sign；
for(；isspace(*s)；s++)；
sign=(*s==’-’) -1:1；
if(*s==’+’||*s==’-’) s++；
for(n=0；isdigit(*s)；s++)
n=10*n+( *s-’0’)；
return sign*n；
参考答案：6354
解析： 函数fun的第一个for循环跳过字符串的前导空白符，接着判断第一个非空白符是否是负号，若是，则置变量sign为-1；否则，置变量sign为1。接着的if语句在第一个非空白字符是负号或正号时，跳过该字符。以后的for循环将后面的数字符当作十进制数的各位数字转换为一个长整数n，当遇字符a时，结束循环。最后，函数返回sign与n的乘积。所以若调用函数时提供的实参是“∪∪6354abc”，则函数的返回值是6354。
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