论述题3：已知C源程序如下：/*longIntAdd*/#include＜stdio.h＞#include＜string.h＞#define LENGTH 81void addLInt(char s1[],char s2[]);void reverse(char s[]);int main(){char intstr1[LENGTH],intstr2[LENGTH];printf("请输入超长整数的被加数和加数:\n");scanf("%s%s",intstr1,intstr2);addLInt(intstr1,intstr2);printf("超长整数和为:%s",intstr1);return 0;}void addLInt(char s1[],char s2[]){int i=0,tmp,c=0;char s[LENGTH];if(strlen(s1)＜strlen(s2)){strcpy(s,s1);strcpy(s1,s2);strcpy(s2,s);}reverse(s1);reverse(s2);while(s2[i]!=;\0’){tmp=s1[i]-’0’+s2[i]-’0’+c;81[i]=tmp%10+’0’;c=tmp/10;i++;}while(si[1]!=’\0’&&c){tmp=s1[i]-’0’+c;s1[i]=tmp%10+’0’;c=tmp/10;i++;}If(c){s1[i++]=c+’0’;s1[i]=’\0’;}reverse(s1);}void reverse(char s[]){int i,j,c;for(i=0,j=strlen(s)-1;i＜j;i++,j--){c=s[i];s[i]=s[j];s[j]=c;}}

设计一组测试用例，使该程序addLInt函数的语句覆盖率和分支覆盖率均能达到100%。如果认为该函数的语句覆盖率或分支覆盖率无法达到100%，需说明为什么。