问题
解答题
求值sin2120°+cos180°+tan45°-cos2(-330°)+sin(-210°)
答案
sin2120°+cos180°+tan45°-cos2-(-330°)+sin(-210°)
=(
)2-1+1-cos230°-sin210°3 2
=
-( 3 4
)2+sin30°=sin30°3 2
=
.1 2
故答案为
.1 2
求值sin2120°+cos180°+tan45°-cos2(-330°)+sin(-210°)
sin2120°+cos180°+tan45°-cos2-(-330°)+sin(-210°)
=(
)2-1+1-cos230°-sin210°3 2
=
-( 3 4
)2+sin30°=sin30°3 2
=
.1 2
故答案为
.1 2