问题
解答题
求
|
答案
=cos190°•(-sin210°) cos350°•(-tan585°)
=cos(180°+10°)•sin(180°+30°) cos(360°-10°)•tan(360°+225°) (-cos10°)•(-sin30°) cos10°•tan225°
=
=sin30° tan(180°+45°)
=sin30° tan45°
.1 2
求
|
=cos190°•(-sin210°) cos350°•(-tan585°)
=cos(180°+10°)•sin(180°+30°) cos(360°-10°)•tan(360°+225°) (-cos10°)•(-sin30°) cos10°•tan225°
=
=sin30° tan(180°+45°)
=sin30° tan45°
.1 2