问题
解答题
求值:
(1)sin120°+cos180°+tan225°-cos(-30°)
(2)tan675°+tan765°-tan(-330°)+tan(-690°)
答案
(1)原式=sin120°+cos180°+tan45°-cos30°=
-1+1-3 2
=0;3 2
(2)原式=-tan45°+tan45°-tan30°+tan30°=-1+1-
+3 3
=0.3 3
求值:
(1)sin120°+cos180°+tan225°-cos(-30°)
(2)tan675°+tan765°-tan(-330°)+tan(-690°)
(1)原式=sin120°+cos180°+tan45°-cos30°=
-1+1-3 2
=0;3 2
(2)原式=-tan45°+tan45°-tan30°+tan30°=-1+1-
+3 3
=0.3 3