问题
填空题
设cos(-80°)=k,那么tan100°=______.
答案
∵sin80°=
=1-cos 280°
=1-cos 2(-80°)
,1-k2
所以tan100°=-tan80°=-
=-sin80° cos80°
=-sin80° cos(-80°)
.1-k2 k
故答案为:-
.1-k2 k
设cos(-80°)=k,那么tan100°=______.
∵sin80°=
=1-cos 280°
=1-cos 2(-80°)
,1-k2
所以tan100°=-tan80°=-
=-sin80° cos80°
=-sin80° cos(-80°)
.1-k2 k
故答案为:-
.1-k2 k