问题
解答题
化简
|
答案
=sin(2π-α)cos(π+α)cos(
+α)cos(π 2
π-α)11 2 cos(π-α)sin(3π-α)sin(-π-α)sin(
π+α)9 2
=-tanα．-sinα•(-cosα)(-sinα)(-sinα) -cosα•sinα•sinα•cosα
搜题请搜索小程序“爱下问搜题”
化简
|
=sin(2π-α)cos(π+α)cos(
+α)cos(π 2
π-α)11 2 cos(π-α)sin(3π-α)sin(-π-α)sin(
π+α)9 2
=-tanα．-sinα•(-cosα)(-sinα)(-sinα) -cosα•sinα•sinα•cosα