问题
解答题
(1)计算
(2)求证:tgx+ctgx=
(3)△ABC中,∠A=45°,∠B=75°,AB=12,求BC的长. |
答案
(1)原式═
=-sin45°+tg(-30°) -cos60°
;3
+22 3 3
(2)证:左边=
+sinx cosx
=cosx sinx
=右边;2 sin2x
(3)由正弦定理可知:BC=
=4AB•sinA sinC
.6
(1)计算
(2)求证:tgx+ctgx=
(3)△ABC中,∠A=45°,∠B=75°,AB=12,求BC的长. |
(1)原式═
=-sin45°+tg(-30°) -cos60°
;3
+22 3 3
(2)证:左边=
+sinx cosx
=cosx sinx
=右边;2 sin2x
(3)由正弦定理可知:BC=
=4AB•sinA sinC
.6