问题 解答题
已知cos(75°+α)=
1
3
,其中-180°<α<-90°
,求sin(105°-α)+cos(375°-α)的值.
答案

原式=sin(105°-α)+cos(375°-α)=sin(75°+α)+cos(15°-α)=2sin(75°+α),

cos(75°+α)=

1
3
,且-105°<75°+α<-15°,

∴sin(75°+α)<0,∴sin(75°+α)=-

1-cos2(75°+α)
=-
2
2
3

故 sin(105°-α)+cos(375°-α)=-

4
3
2

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