问题 计算题

如图所示的滑轮组,每个滑轮等重,不计绳重和摩擦。物体重G从200N开始逐渐增加,直到1600N时绳子被拉断。每次都匀速拉动绳子将物体提升同样的高度。右图记录了在此过程中滑轮组的机械效率随物体重力的增加而变化的图像。求:

(1) 每个滑轮重多少N?

(2) 绳子能承受的最大拉力是多少N?

(3) 当滑轮组的机械效率低于多少时,使用它将不再省力?

答案

(1)200N(2)600N(3)33.3%.

右图记录了在此过程中滑轮组的机械效率随物体重力的增加而变化的图像。由图可知物重为200N时,

滑轮组的机械效率为50%。G动=3F-G物=200N。物体重G从200N开始逐渐增加,直到1600N时绳子被拉断。F=1/3(G动+G物)="600N." 当滑轮组不再省力时,拉力等于物重。G动=3F-G物,即F="G," G动=3F-F=2F,此时滑轮组的机械效率为=33.3%.

(1)由图可知物重为200N时,滑轮组的机械效率为50%。每个滑轮重

G动=3F-G物=200N。

(2)物体重G从200N开始逐渐增加,直到1600N时绳子被拉断。

F=1/3(G动+G物)=600N.

(3)当滑轮组不再省力时,拉力等于物重。

G动=3F-G物,即F="G," G动=3F-F=2F,

此时滑轮组的机械效率为=33.3%.

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