下列化学方程式书写正确且符合题意的是（ ）
A．高温锻炼石灰石：CaC03
CaO+CO2↑--------分解反应高温 ═
B．炼铁的主要原理反应：Fe2O3
2Fe+3CO2------置换反应高温 ═
C．盐酸除铁锈：6HCl+Fe2O3═2FeCl2+3H20----复分解反应
D．检验二氧化碳气体：CO2+2NaOH═Na2CO3+H2O---复分解反应
选项B中反应物一氧化碳的化学式没有写在化学方程式中，因此化学方程式的书写错误；炼铁反应是两种化合物反应，不是一种单质与一种化合物反应，不符合置换反应的概念，反应类型的判断也不正确．故选项B错误．
选项C中盐酸与氧化铁的反应属于复分解反应，复分解反应中元素的化合价不变，因此应生成氯化铁，而不是氯化亚铁，因此选项C错误．
选项D中的反应不是两种化合物互相交换成分生成另外两种化合物的反应，因此不是复分解反应；该反应能发生，但不能产生明显现象，因此不符合题意．故选项D错误．
只有选项A正确．
故选A．
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