问题 问答题

晶胞是晶体中最小的重复单位,数目巨大的晶胞无隙并置构成晶体.NaCl晶体是一个正六面体(如图一).我们把阴、阳离子看成不等径的圆球,并彼此相切(已知a为常数).

请计算下列问题:

(1)每个晶胞平均分摊______个Na+,______个Cl-

(2)NaCl晶体中阴阳离子的最短距离为______(用a表示).

(3)NaCl晶体为“巨分子”,在高温下(≥1413℃时)晶体转变成气态团簇分子.现有1molNaCl晶体,加强热使其气化,测得气体体积为11.2L(已折算为标准状况).则此时氯化钠气体的分子式为______.

答案

(1)该晶胞中钠离子个数=12×

1
4
+1=4,氯离子个数=8×
1
8
+6×
1
2
=4

故答案为:4,4;

(2)根据图片二知,NaCl晶体中阴阳离子的最短距离为a的一半即

a
2

故答案为:

a
2

(3)1mol氯化钠的质量=1mol×58.8g/mol=58.5g,标况下,气体体积为11.2L的氯化钠的物质的量=

11.2L
22.4L/mol

=0.5mol,M=

58.5g
0.5mol
=117g/mol,所以氯化钠气体的分子式为Na2Cl2

故答案为:Na2Cl2

判断题
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