问题
选择题
y=sinxsin(x+
|
答案
y=sinxcosx+
cos2x=3 2
sin2x+1 2
cos2x=sin(2x+3 2
),π 3
故最大值为1,最小正周期为T=
=π.2π 2
故选D.
y=sinxsin(x+
|
y=sinxcosx+
cos2x=3 2
sin2x+1 2
cos2x=sin(2x+3 2
),π 3
故最大值为1,最小正周期为T=
=π.2π 2
故选D.