问题
问答题
如图所示,质量为10kg的物体A静止在斜面上,试画出物体所受重力的示意图.

答案
G=mg=10kg×9.8N/kg=98N.
过重心作竖直向下、大小为98N的重力.如图所示
如图所示,质量为10kg的物体A静止在斜面上,试画出物体所受重力的示意图.
G=mg=10kg×9.8N/kg=98N.
过重心作竖直向下、大小为98N的重力.如图所示
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