问题
选择题
函数y=sin(
|
答案
函数y=sin(
+2x)sin(π 4
-2x)π 4
=sin(
+2x)sin[π 4
-(π 2
+2x)]π 4
=
×2sin(1 2
+2x)cos(π 4
+2x)π 4
=
sin(4x+1 2
),π 2
∵ω=4,∴T=
=2π ω
.π 2
故选C
函数y=sin(
|
函数y=sin(
+2x)sin(π 4
-2x)π 4
=sin(
+2x)sin[π 4
-(π 2
+2x)]π 4
=
×2sin(1 2
+2x)cos(π 4
+2x)π 4
=
sin(4x+1 2
),π 2
∵ω=4,∴T=
=2π ω
.π 2
故选C