问题
解答题
求函数y=2cos(x+
|
答案
y=2cos(x+
)cos(x-π 4
)+π 4
sin2x3
=2(
cos2x-1 2
sin2x)+1 2
sin2x3
=cos2x+
sin2x3
=2sin(2x+
)π 6
∴函数y=2cos(x+
)cos(x-π 4
)+π 4
sin2x的值域是[-2,2],3
最小正周期是π;
求函数y=2cos(x+
|
y=2cos(x+
)cos(x-π 4
)+π 4
sin2x3
=2(
cos2x-1 2
sin2x)+1 2
sin2x3
=cos2x+
sin2x3
=2sin(2x+
)π 6
∴函数y=2cos(x+
)cos(x-π 4
)+π 4
sin2x的值域是[-2,2],3
最小正周期是π;