问题
填空题
函数y=1-sin2(x-
|
答案
函数y=1-sin2(x-
)π 6
=1-1-cos(2x-
)π 3 2
=1+cos(2x-
)π 3 2
=
cos(2x-1 2
)+π 3 1 2
最小正周期T=π
故应填π.
函数y=1-sin2(x-
|
函数y=1-sin2(x-
)π 6
=1-1-cos(2x-
)π 3 2
=1+cos(2x-
)π 3 2
=
cos(2x-1 2
)+π 3 1 2
最小正周期T=π
故应填π.