The addition problem above shows four of the 24 different integers that can be formed by using each of the digits 1, 2, 3 and 4 exactly once in each integer. What is the sum of these 24 integers ?()
参考答案:66660
解析:
根据题意可知1,2,3和4共可构成[*]个四位整数,四个数字在每个四位整数中出仅现一次。在这24个四位整数中,1,2,3和4在个位,十位,百位和千位上出现的概率相同,均6次。因此个位,十位,百位和千位相加的和均为(1+2+3+4)×6=60,所以这24个四位整数的和为:60(1000+100+10+1)=66660