问题
填空题
函数y=sin(
|
答案
∵f(x)=sin(
-2x)+cos2x=π 3
cos2x-3 2
sin2x+cos2x=( 1 2
+1)cos2x-3 2
sin2x1 2
=
sin(2x+θ)2+ 3
∴T=
=π2π 2
故答案为:π.
函数y=sin(
|
∵f(x)=sin(
-2x)+cos2x=π 3
cos2x-3 2
sin2x+cos2x=( 1 2
+1)cos2x-3 2
sin2x1 2
=
sin(2x+θ)2+ 3
∴T=
=π2π 2
故答案为:π.