问题
填空题
函数y=sin2xcos2x最小正周期是______.
答案
y=sin2xcos2x=
•4sin2xcos2x1 4
=
sin22x=1 4
•1 4 1-cos4x 2
=
-1 8
cos4x.1 8
所以T=
=2π 4
.π 2
故答案为
.π 2
函数y=sin2xcos2x最小正周期是______.
y=sin2xcos2x=
•4sin2xcos2x1 4
=
sin22x=1 4
•1 4 1-cos4x 2
=
-1 8
cos4x.1 8
所以T=
=2π 4
.π 2
故答案为
.π 2