问题
填空题
已知圆C:(x-2)2+(y-1)2=2,过原点的直线l与圆C相切,则所有过原点的切线的斜率之和为______.
答案
设直线方程为y=kx,即kx-y=0
圆心到直线的距离为d=
=|2k-1| k2+1 2
∴2k2-4k-1=0
∴所有过原点的切线的斜率之和为2
故答案为2.
已知圆C:(x-2)2+(y-1)2=2,过原点的直线l与圆C相切,则所有过原点的切线的斜率之和为______.
设直线方程为y=kx,即kx-y=0
圆心到直线的距离为d=
=|2k-1| k2+1 2
∴2k2-4k-1=0
∴所有过原点的切线的斜率之和为2
故答案为2.
完形填空。 | ||||
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