,则z的取值范围是().
参考答案:(-1,3)
解析:
从而有x2-2x-3<0,(x-3)(x+1)<0,则-1<x<3,即x∈(-1,3).
—Betty, come and have a look.
—Oh, ______ nice Mp4 player! I like it. [ ]
A. how
B. what
C. what a
D. how a
设g(x)可导,且x→0时,g(x)是x的高阶无穷小,则当x→0时,必有 (A) g′(x)是无穷小量. (B)
是x2的高阶无穷小. (C)
是无穷大量. (D) 若G′(x)=g(x),则G(x)是x高阶无穷小.