问题
解答题
(1)化简
(2)tanx=2,求2sin2x-sinxcosx+cos2x的值. |
答案
(1)原式=
=-1-sinα(-cosα) -cosαsinα
(2)2sin2x-sinxcosx+cos2x=
=2sin2x-sinxcosx+cos2x sin2x+cos2x
=2tan2x-tanx+1 tan2x+1 7 5
(1)化简
(2)tanx=2,求2sin2x-sinxcosx+cos2x的值. |
(1)原式=
=-1-sinα(-cosα) -cosαsinα
(2)2sin2x-sinxcosx+cos2x=
=2sin2x-sinxcosx+cos2x sin2x+cos2x
=2tan2x-tanx+1 tan2x+1 7 5