问题
填空题
直线xcos140°+ysin140°+1=0的倾斜角为______．
答案
直线xcos140°+ysin140°+1=0的斜率
k=-
=cos140° sin140°
=cos40° sin40°
=tan50°，sin50° cos50°
所以该直线的倾斜角为50°．
搜题请搜索小程序“爱下问搜题”
直线xcos140°+ysin140°+1=0的倾斜角为______．
直线xcos140°+ysin140°+1=0的斜率
k=-
=cos140° sin140°
=cos40° sin40°
=tan50°，sin50° cos50°
所以该直线的倾斜角为50°．