问题
解答题
设向量
(1)若
(2)求|
(3)若
|
答案
(1)∵
=(4cosα,sinα),. a
=(sinβ,4cosβ),. b
=(cosβ,-4sinβ).. c
∴
•a
=4cosαsinβ+4sinαcosβ=4sin(α+β),b
•a
=4cos(α+β),c
∵
•(a
-2b
)=0,c
∴
•a
=2b
•a
,c
∴4sin(α+β)=8cos(α+β),
即tan(α+β)=2
(2)∵|
+b
|=c
=(sinβ+cosβ)2+(4cosβ-4sinβ)2
≤417-15sin2β
,2
即|
+b
|的最大值为4c 2
(3)∵
∥a
∴16cosαcosβ-sinαsinβ=0,tanαtanβ=16,b
=cos(α+β) cos(α-β)
=-1-tanαtanβ 1+tanαtanβ 15 17