问题
填空题
若|m-1|+(
|
答案
∵|m-1|+(
-5)2=0,n
∴m-1=0,
-5=0,n
解得m=1,n=25,
∴mx2-ny2=x2-25y2=(x+5y)(x-5y).
故答案为:(x+5y)(x-5y).
若|m-1|+(
|
∵|m-1|+(
-5)2=0,n
∴m-1=0,
-5=0,n
解得m=1,n=25,
∴mx2-ny2=x2-25y2=(x+5y)(x-5y).
故答案为:(x+5y)(x-5y).