问题
解答题
计算或化简: (1)11-13+18; (2)-12-6÷(-2)×
(3)38°45′+72.5°(结果用度分秒表示); (4)2(a2-ab)-3(
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答案
解
(1)原式=-2+18=16;
(2)原式=-1+3×3
=-1+9
=8;
(3)38°45′+72°30′
=110°75′
=111°15′;
(3)原式=2a2-2ab-2a2+3ab
=ab.
计算或化简: (1)11-13+18; (2)-12-6÷(-2)×
(3)38°45′+72.5°(结果用度分秒表示); (4)2(a2-ab)-3(
|
解
(1)原式=-2+18=16;
(2)原式=-1+3×3
=-1+9
=8;
(3)38°45′+72°30′
=110°75′
=111°15′;
(3)原式=2a2-2ab-2a2+3ab
=ab.