问题
解答题
计算: (1)-
(2)
(3)-32+5×(-
(4)2×[9+2(
|
答案
(1)原式=-
×(-8+3 4
)1 3
=-
×(-3 4
)23 3
=5
;3 4
(2)原式=-2-11
=-13;
(3)原式=-9-8-16÷(-8)
=-9-8+2
=-15;
(4)原式=2×[9+2
-4]+25
=2×(5+2
)+25
=10+4
+25
≈20.94.
计算: (1)-
(2)
(3)-32+5×(-
(4)2×[9+2(
|
(1)原式=-
×(-8+3 4
)1 3
=-
×(-3 4
)23 3
=5
;3 4
(2)原式=-2-11
=-13;
(3)原式=-9-8-16÷(-8)
=-9-8+2
=-15;
(4)原式=2×[9+2
-4]+25
=2×(5+2
)+25
=10+4
+25
≈20.94.