问题
解答题
计算 (1)3×(-4)+(-4)2÷(-8) (2)
(3)求代数式(2a2-5a)-2(3a-5+a2)的值,其中a=-1. |
答案
(1)原式=-12+16÷(-8)
=-12-2
=-14;
(2)原式=4-3×7
=4-21
=-17;
(3)原式=2a2-5a-6a+10-2a2
=-11a+10,
当a=-1时,
原式=-11×(-1)+10
=21.
计算 (1)3×(-4)+(-4)2÷(-8) (2)
(3)求代数式(2a2-5a)-2(3a-5+a2)的值,其中a=-1. |
(1)原式=-12+16÷(-8)
=-12-2
=-14;
(2)原式=4-3×7
=4-21
=-17;
(3)原式=2a2-5a-6a+10-2a2
=-11a+10,
当a=-1时,
原式=-11×(-1)+10
=21.