问题
选择题
在△ABC中,(
|
答案
∵(
+BC
)•BA
=|AC
|2AC
∴(
+BC
-BA
)•AC
=0AC
则有
•BA
=0AC
∴BA⊥AC 即∠A=90°
∵|
|=2,则|BC
|=2cosB,|AC
|=2sinBAB
∵
•BA
=3,∴4cos2B=3BC
∴cosB=
,sinB=3 2 1 2
∴S△ABC=
×1× 1 2
=3 3 2
故选:A