问题 填空题
化简
sin(2π-α)cos(π+α)
cos(π-α)sin(3π-α)sin(-α-π)
=______.
答案

sin(2π-α)cos(π+α)
cos(π-α)sin(3π-α)sin(-α-π)
=
-sinα•(-cosα)
-cosα•sinα•sinα
=-
1
sinα

故答案为-

1
sinα

实验题
判断题