问题
选择题
设F1,F2是双曲线
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答案
由题意得,△PF1F2是直角三角形,
由勾股定理得 (2c)2=|PF1|2+|PF2|2=|PF1-PF2|2-2|
||PF1
|=4a2-4ac,∴c2-ac-a2=0,e2-e-1=0 且e>1,PF2
解方程得e=
,1+ 5 2
故选 A.
设F1,F2是双曲线
|
由题意得,△PF1F2是直角三角形,
由勾股定理得 (2c)2=|PF1|2+|PF2|2=|PF1-PF2|2-2|
||PF1
|=4a2-4ac,∴c2-ac-a2=0,e2-e-1=0 且e>1,PF2
解方程得e=
,1+ 5 2
故选 A.
选择方框中所给词组填空。 | |
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1. Outgoing people arc easy to _ . 2. I'm afraid of speaking many people. 3. If you can't sleep at night, why not _ before going co bed? 4. Every time we don't know what to do, my father will ___ some good ideas. 5. Nobody could take away the books from the . |