问题
解答题
若α=
(1)sin(-α-5π)•cos(α-
(2)
|
答案
(1)sin(-α-5π)•cos(α-
)=sin2α=(π 2
)2=2 2
.1 2
(2)
=sinα-cosα tanα-1
•cosα=cosα=cossinα-cosα sinα-cosα
=π 4
.2 2
若α=
(1)sin(-α-5π)•cos(α-
(2)
|
(1)sin(-α-5π)•cos(α-
)=sin2α=(π 2
)2=2 2
.1 2
(2)
=sinα-cosα tanα-1
•cosα=cosα=cossinα-cosα sinα-cosα
=π 4
.2 2