问题
填空题
已知(x+
|
答案
(x+
)(y+x2+2010
)=2010y2+2010
故y+
=y2+2010
=2010 (x+
)x2+2010
=2010(
-x)x2+2010 2010
-xx2+2010
同理x+
=x2+2010
-y.y2+2010
两式相加可得x+y=0.
则x2-3xy-4y2-6x-6y=(x+y)(x-4y)-6(x+y)=0.
故答案是:0.