问题 解答题
已知向量
OA
=(3,-4),
OB
=(6,-3),
OC
=(5-m,-3-m).
(Ⅰ)若点A、B、C共线,求实数m的值;
(Ⅱ)若△ABC为直角三角形,且∠B为直角,求实数m的值.
答案

(Ⅰ)∵

OA
=(3,-4),
OB
=(6,-3),
OC
=(5-m,-3-m),

AB
=(3,1),
AC
=(2-m,1-m),(2分)

由A、B、C三点共线得3(1-m)=2-m,(4分)

解得m=

1
2
.(6分)

(Ⅱ)由题设

BA
=(-3,-1),
BC
=(-1-m,-m),

∵∠B为直角,∴

BA
BC
=0,(10分)

∴3+3m+m=0,解得m=-

3
4
.(12分)

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