问题
填空题
|
|
答案
原式=-(
-1 1001
)-(1 1000
-1 1002
)-[-(1 1001
-1 1002
)]1 1000
=-
+1 1001
-1 1000
+1 1002
+1 1001
-1 1002 1 1000
=0,
故答案为0.
|
|
原式=-(
-1 1001
)-(1 1000
-1 1002
)-[-(1 1001
-1 1002
)]1 1000
=-
+1 1001
-1 1000
+1 1002
+1 1001
-1 1002 1 1000
=0,
故答案为0.