问题
选择题
△ABC中,
|
答案
∵
=(cosA,sinA),m
=(cosB,-sinB),n
∴
•m
=cosAcosB-sinAsinB=cos(A+B)=cos(π-C)=-cosC,n
∴-cosC=
,得cosC=-1 2
.1 2
∵0<C<π.
∴C=
.2π 3
故选B.
△ABC中,
|
∵
=(cosA,sinA),m
=(cosB,-sinB),n
∴
•m
=cosAcosB-sinAsinB=cos(A+B)=cos(π-C)=-cosC,n
∴-cosC=
,得cosC=-1 2
.1 2
∵0<C<π.
∴C=
.2π 3
故选B.