问题
解答题
已知
(1)
|
答案
∵
=3,∴tanα=1+tanα 1-tanα
.1 2
(1)
=2sinα-3cosα 4sinα-9cosα
=2tanα-3 4tanα-9
.2 7
(2)
=2sinαcosα+6cos2α-3 5-10sin2α-6sinαcosα
=2tanα+6-3(tan2α+1) 5(tan2α+1)-10tan2α-6tanα
.13 3
已知
(1)
|
∵
=3,∴tanα=1+tanα 1-tanα
.1 2
(1)
=2sinα-3cosα 4sinα-9cosα
=2tanα-3 4tanα-9
.2 7
(2)
=2sinαcosα+6cos2α-3 5-10sin2α-6sinαcosα
=2tanα+6-3(tan2α+1) 5(tan2α+1)-10tan2α-6tanα
.13 3