问题 解答题
阅读下面问题:
1
1+
2
=
1×(
2
-1)
(
2
+1)(
2
-1)
=
2
-1
1
3
+
2
=
3
-
2
(
3
+
2
)(
3
-
2
)
=
3
-
2
1
5
+2
=
5
-2
(
5
+2)(
5
-2)
=
5
-2

试求:(1)
1
7
+
6
的值;
(2)
1
3
2
+
17
的值;
(3)
1
n+1
+
n
(n为正整数)的值.
答案

(1)原式=

7
-
6
(
7
+
6
)(
7
-
6
)
=
7
-
6

(2)原式=

3
2
-
17
(3
2
+
17
)(3
2
-
17
)
=3
2
-
17

(3)原式=

n+1
-
n
(
n+1
+
n
)(
n+1
-
n
)
=
n+1
-
n

填空题
单项选择题 A1/A2型题